x^2+80x-50=0

Solution for x^2+80x-50=0 equation:

x^2+80x-50=0

a = 1; b = 80; c = -50;
Δ = b2-4ac
Δ = 802-4·1·(-50)
Δ = 6600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6600}=\sqrt{100*66}=\sqrt{100}*\sqrt{66}=10\sqrt{66}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-10\sqrt{66}}{2*1}=\frac{-80-10\sqrt{66}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+10\sqrt{66}}{2*1}=\frac{-80+10\sqrt{66}}{2}
$